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201340343441 is a prime number
BaseRepresentation
bin1011101110000011010…
…0011101010010010001
3201020200202101012001002
42323200310131102101
511244321111442231
6232254450151345
720355254452556
oct2734064352221
9636622335032
10201340343441
117842a414056
1233030582555
1315ca8c110c3
149a60104a2d
155385e830cb
hex2ee0d1d491

201340343441 has 2 divisors, whose sum is σ = 201340343442. Its totient is φ = 201340343440.

The previous prime is 201340343431. The next prime is 201340343461. The reversal of 201340343441 is 144343043102.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 187832092816 + 13508250625 = 433396^2 + 116225^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201340343441 is a prime.

It is not a weakly prime, because it can be changed into another prime (201340343431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100670171720 + 100670171721.

It is an arithmetic number, because the mean of its divisors is an integer number (100670171721).

Almost surely, 2201340343441 is an apocalyptic number.

It is an amenable number.

201340343441 is a deficient number, since it is larger than the sum of its proper divisors (1).

201340343441 is an equidigital number, since it uses as much as digits as its factorization.

201340343441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 201340343441 its reverse (144343043102), we get a palindrome (345683386543).

The spelling of 201340343441 in words is "two hundred one billion, three hundred forty million, three hundred forty-three thousand, four hundred forty-one".