Base | Representation |
---|---|
bin | 1001001001111110100101… |
… | …11101101110101101010011 |
3 | 2122021210111122021122200211 |
4 | 10210333102331232231103 |
5 | 10114334014041120221 |
6 | 110453242210424551 |
7 | 4145431361466445 |
oct | 444772275565523 |
9 | 78253448248624 |
10 | 20134051113811 |
11 | 6462891a61a08 |
12 | 2312144b92157 |
13 | b3082c56531b |
14 | 4d86c9784495 |
15 | 24daed6b96e1 |
hex | 124fd2f6eb53 |
20134051113811 has 2 divisors, whose sum is σ = 20134051113812. Its totient is φ = 20134051113810.
The previous prime is 20134051113767. The next prime is 20134051113817. The reversal of 20134051113811 is 11831115043102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20134051113811 - 217 = 20134050982739 is a prime.
It is not a weakly prime, because it can be changed into another prime (20134051113817) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067025556905 + 10067025556906.
It is an arithmetic number, because the mean of its divisors is an integer number (10067025556906).
Almost surely, 220134051113811 is an apocalyptic number.
20134051113811 is a deficient number, since it is larger than the sum of its proper divisors (1).
20134051113811 is an equidigital number, since it uses as much as digits as its factorization.
20134051113811 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 31.
Adding to 20134051113811 its reverse (11831115043102), we get a palindrome (31965166156913).
The spelling of 20134051113811 in words is "twenty trillion, one hundred thirty-four billion, fifty-one million, one hundred thirteen thousand, eight hundred eleven".
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