Base | Representation |
---|---|
bin | 10010110000000101… |
… | …101010010101010101 |
3 | 1220222011221110021202 |
4 | 102300011222111111 |
5 | 312213320041232 |
6 | 13125520322245 |
7 | 1311641252201 |
oct | 226005522525 |
9 | 56864843252 |
10 | 20134143317 |
11 | 85a2220972 |
12 | 3a9aa73385 |
13 | 1b8b414292 |
14 | d90043b01 |
15 | 7cc917162 |
hex | 4b016a555 |
20134143317 has 2 divisors, whose sum is σ = 20134143318. Its totient is φ = 20134143316.
The previous prime is 20134143311. The next prime is 20134143331. The reversal of 20134143317 is 71334143102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19949020081 + 185123236 = 141241^2 + 13606^2 .
It is a cyclic number.
It is not a de Polignac number, because 20134143317 - 24 = 20134143301 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20134143317.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20134143311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067071658 + 10067071659.
It is an arithmetic number, because the mean of its divisors is an integer number (10067071659).
Almost surely, 220134143317 is an apocalyptic number.
It is an amenable number.
20134143317 is a deficient number, since it is larger than the sum of its proper divisors (1).
20134143317 is an equidigital number, since it uses as much as digits as its factorization.
20134143317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 20134143317 its reverse (71334143102), we get a palindrome (91468286419).
The spelling of 20134143317 in words is "twenty billion, one hundred thirty-four million, one hundred forty-three thousand, three hundred seventeen".
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