Base | Representation |
---|---|
bin | 1011101110000011111… |
… | …1110100011110111001 |
3 | 201020200221222111220121 |
4 | 2323200333310132321 |
5 | 11244322342301131 |
6 | 232255034053241 |
7 | 20355321666541 |
oct | 2734077643671 |
9 | 636627874817 |
10 | 201343322041 |
11 | 78431068a04 |
12 | 3303157a221 |
13 | 15ca9714aa4 |
14 | 9a6067c321 |
15 | 5386370911 |
hex | 2ee0ff47b9 |
201343322041 has 2 divisors, whose sum is σ = 201343322042. Its totient is φ = 201343322040.
The previous prime is 201343322023. The next prime is 201343322051. The reversal of 201343322041 is 140223343102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 201267979641 + 75342400 = 448629^2 + 8680^2 .
It is a cyclic number.
It is not a de Polignac number, because 201343322041 - 231 = 199195838393 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 201343321997 and 201343322015.
It is not a weakly prime, because it can be changed into another prime (201343322051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100671661020 + 100671661021.
It is an arithmetic number, because the mean of its divisors is an integer number (100671661021).
Almost surely, 2201343322041 is an apocalyptic number.
It is an amenable number.
201343322041 is a deficient number, since it is larger than the sum of its proper divisors (1).
201343322041 is an equidigital number, since it uses as much as digits as its factorization.
201343322041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 201343322041 its reverse (140223343102), we get a palindrome (341566665143).
The spelling of 201343322041 in words is "two hundred one billion, three hundred forty-three million, three hundred twenty-two thousand, forty-one".
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