201344054411 has 2 divisors, whose sum is σ = 201344054412. Its totient is φ = 201344054410.

The previous prime is 201344054393. The next prime is 201344054413. The reversal of 201344054411 is 114450443102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-201344054411 is a prime.

Together with 201344054413, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (201344054413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100672027205 + 100672027206.

It is an arithmetic number, because the mean of its divisors is an integer number (100672027206).

Almost surely, 2^201344054411 is an apocalyptic number.

201344054411 is a deficient number, since it is larger than the sum of its proper divisors (1).

201344054411 is an equidigital number, since it uses as much as digits as its factorization.

201344054411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7680, while the sum is 29.

Adding to 201344054411 its reverse (114450443102), we get a palindrome (315794497513).

The spelling of 201344054411 in words is "two hundred one billion, three hundred forty-four million, fifty-four thousand, four hundred eleven".