Base | Representation |
---|---|
bin | 10010110000000110… |
… | …110011000010100011 |
3 | 1220222012111120210121 |
4 | 102300012303002203 |
5 | 312213404103443 |
6 | 13125530541111 |
7 | 1311643632346 |
oct | 226006630243 |
9 | 56865446717 |
10 | 20134441123 |
11 | 85a2404695 |
12 | 3a9ab97797 |
13 | 1b8b4b99b4 |
14 | d900c045d |
15 | 7cc9754ed |
hex | 4b01b30a3 |
20134441123 has 2 divisors, whose sum is σ = 20134441124. Its totient is φ = 20134441122.
The previous prime is 20134441111. The next prime is 20134441127. The reversal of 20134441123 is 32114443102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20134441123 - 225 = 20100886691 is a prime.
It is a super-2 number, since 2×201344411232 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20134441127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067220561 + 10067220562.
It is an arithmetic number, because the mean of its divisors is an integer number (10067220562).
Almost surely, 220134441123 is an apocalyptic number.
20134441123 is a deficient number, since it is larger than the sum of its proper divisors (1).
20134441123 is an equidigital number, since it uses as much as digits as its factorization.
20134441123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 20134441123 its reverse (32114443102), we get a palindrome (52248884225).
The spelling of 20134441123 in words is "twenty billion, one hundred thirty-four million, four hundred forty-one thousand, one hundred twenty-three".
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