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20135494370773 is a prime number
BaseRepresentation
bin1001001010000001010001…
…11111010100010111010101
32122021221020020000201001101
410211000220333110113111
510114344443024331043
6110454041324430101
74145512215123625
oct445005077242725
978257206021041
1020135494370773
116463462706261
1223124883a8331
13b309cc57ac22
144d87c5316885
1524db8525624d
hex125028fd45d5

20135494370773 has 2 divisors, whose sum is σ = 20135494370774. Its totient is φ = 20135494370772.

The previous prime is 20135494370713. The next prime is 20135494370819. The reversal of 20135494370773 is 37707349453102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16364468271204 + 3771026099569 = 4045302^2 + 1941913^2 .

It is a cyclic number.

It is not a de Polignac number, because 20135494370773 - 29 = 20135494370261 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20135494370713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067747185386 + 10067747185387.

It is an arithmetic number, because the mean of its divisors is an integer number (10067747185387).

Almost surely, 220135494370773 is an apocalyptic number.

It is an amenable number.

20135494370773 is a deficient number, since it is larger than the sum of its proper divisors (1).

20135494370773 is an equidigital number, since it uses as much as digits as its factorization.

20135494370773 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13335840, while the sum is 55.

The spelling of 20135494370773 in words is "twenty trillion, one hundred thirty-five billion, four hundred ninety-four million, three hundred seventy thousand, seven hundred seventy-three".