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20135741402531 is a prime number
BaseRepresentation
bin1001001010000001101111…
…01101101010110110100011
32122021221212102212012220202
410211000313231222312203
510114400444244340111
6110454122031255415
74145521304634056
oct445006755526643
978257772765822
1020135741402531
11646357a0a1937
12231253707a56b
13b30a3b7c1571
144d880a05ca9d
1524db9bca0b3b
hex125037b6ada3

20135741402531 has 2 divisors, whose sum is σ = 20135741402532. Its totient is φ = 20135741402530.

The previous prime is 20135741402503. The next prime is 20135741402549. The reversal of 20135741402531 is 13520414753102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20135741402531 - 222 = 20135737208227 is a prime.

It is a super-2 number, since 2×201357414025312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20135741432531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067870701265 + 10067870701266.

It is an arithmetic number, because the mean of its divisors is an integer number (10067870701266).

Almost surely, 220135741402531 is an apocalyptic number.

20135741402531 is a deficient number, since it is larger than the sum of its proper divisors (1).

20135741402531 is an equidigital number, since it uses as much as digits as its factorization.

20135741402531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 100800, while the sum is 38.

The spelling of 20135741402531 in words is "twenty trillion, one hundred thirty-five billion, seven hundred forty-one million, four hundred two thousand, five hundred thirty-one".