Base | Representation |
---|---|
bin | 1001001010000011001111… |
… | …00000000111001001000111 |
3 | 2122022000221022111110012201 |
4 | 10211001213200013021013 |
5 | 10114404120021423014 |
6 | 110454333351455331 |
7 | 4145550211466113 |
oct | 445014740071107 |
9 | 78260838443181 |
10 | 20136543154759 |
11 | 646395071a189 |
12 | 231271b687547 |
13 | b30b38938b75 |
14 | 4d8884722743 |
15 | 24dbe7371e74 |
hex | 125067807247 |
20136543154759 has 2 divisors, whose sum is σ = 20136543154760. Its totient is φ = 20136543154758.
The previous prime is 20136543154661. The next prime is 20136543154771. The reversal of 20136543154759 is 95745134563102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20136543154759 - 213 = 20136543146567 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20136543158759) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10068271577379 + 10068271577380.
It is an arithmetic number, because the mean of its divisors is an integer number (10068271577380).
Almost surely, 220136543154759 is an apocalyptic number.
20136543154759 is a deficient number, since it is larger than the sum of its proper divisors (1).
20136543154759 is an equidigital number, since it uses as much as digits as its factorization.
20136543154759 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608000, while the sum is 55.
The spelling of 20136543154759 in words is "twenty trillion, one hundred thirty-six billion, five hundred forty-three million, one hundred fifty-four thousand, seven hundred fifty-nine".
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