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2014001021303 is a prime number
BaseRepresentation
bin11101010011101011110…
…100001100000101110111
321010112111012020102111122
4131103223310030011313
5230444133230140203
64141115211254155
7265335552136115
oct35235364140567
97115435212448
102014001021303
11707151087377
122863b0a4a35b
13117bc514006b
146d69a150ab5
15375c7263538
hex1d4ebd0c177

2014001021303 has 2 divisors, whose sum is σ = 2014001021304. Its totient is φ = 2014001021302.

The previous prime is 2014001021267. The next prime is 2014001021317. The reversal of 2014001021303 is 3031201004102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2014001021303 - 216 = 2014000955767 is a prime.

It is a super-2 number, since 2×20140010213032 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2014001021203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007000510651 + 1007000510652.

It is an arithmetic number, because the mean of its divisors is an integer number (1007000510652).

Almost surely, 22014001021303 is an apocalyptic number.

2014001021303 is a deficient number, since it is larger than the sum of its proper divisors (1).

2014001021303 is an equidigital number, since it uses as much as digits as its factorization.

2014001021303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 2014001021303 its reverse (3031201004102), we get a palindrome (5045202025405).

The spelling of 2014001021303 in words is "two trillion, fourteen billion, one million, twenty-one thousand, three hundred three".