Base | Representation |
---|---|
bin | 11101010011101011110… |
… | …100001100000101110111 |
3 | 21010112111012020102111122 |
4 | 131103223310030011313 |
5 | 230444133230140203 |
6 | 4141115211254155 |
7 | 265335552136115 |
oct | 35235364140567 |
9 | 7115435212448 |
10 | 2014001021303 |
11 | 707151087377 |
12 | 2863b0a4a35b |
13 | 117bc514006b |
14 | 6d69a150ab5 |
15 | 375c7263538 |
hex | 1d4ebd0c177 |
2014001021303 has 2 divisors, whose sum is σ = 2014001021304. Its totient is φ = 2014001021302.
The previous prime is 2014001021267. The next prime is 2014001021317. The reversal of 2014001021303 is 3031201004102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2014001021303 - 216 = 2014000955767 is a prime.
It is a super-2 number, since 2×20140010213032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2014001021203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007000510651 + 1007000510652.
It is an arithmetic number, because the mean of its divisors is an integer number (1007000510652).
Almost surely, 22014001021303 is an apocalyptic number.
2014001021303 is a deficient number, since it is larger than the sum of its proper divisors (1).
2014001021303 is an equidigital number, since it uses as much as digits as its factorization.
2014001021303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 2014001021303 its reverse (3031201004102), we get a palindrome (5045202025405).
The spelling of 2014001021303 in words is "two trillion, fourteen billion, one million, twenty-one thousand, three hundred three".
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