2014014141283 has 2 divisors, whose sum is σ = 2014014141284. Its totient is φ = 2014014141282.

The previous prime is 2014014141257. The next prime is 2014014141329. The reversal of 2014014141283 is 3821414104102.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2014014141283 is a prime.

It is a super-2 number, since 2×2014014141283² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2014014141983) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007007070641 + 1007007070642.

It is an arithmetic number, because the mean of its divisors is an integer number (1007007070642).

Almost surely, 2^{2014014141283} is an apocalyptic number.

2014014141283 is a deficient number, since it is larger than the sum of its proper divisors (1).

2014014141283 is an equidigital number, since it uses as much as digits as its factorization.

2014014141283 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6144, while the sum is 31.

Adding to 2014014141283 its reverse (3821414104102), we get a palindrome (5835428245385).

The spelling of 2014014141283 in words is "two trillion, fourteen billion, fourteen million, one hundred forty-one thousand, two hundred eighty-three".