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2014014141300 = 22352725711233323
BaseRepresentation
bin11101010011101100100…
…110001111001101110100
321010112112002220222202110
4131103230212033031310
5230444200110010200
64141120400411020
7265336101511620
oct35235446171564
97115462828673
102014014141300
11707158528647
122863b5316a70
13117bc7a84a85
146d69bba8180
15375c84a5b50
hex1d4ec98f374

2014014141300 has 288 divisors, whose sum is σ = 6693553585152. Its totient is φ = 458008657920.

The previous prime is 2014014141283. The next prime is 2014014141329. The reversal of 2014014141300 is 31414104102.

It is a super-2 number, since 2×20140141413002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 606081439 + ... + 606084761.

It is an arithmetic number, because the mean of its divisors is an integer number (23241505504).

Almost surely, 22014014141300 is an apocalyptic number.

2014014141300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2014014141300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3346776792576).

2014014141300 is an abundant number, since it is smaller than the sum of its proper divisors (4679539443852).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2014014141300 is a wasteful number, since it uses less digits than its factorization.

2014014141300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4727 (or 4720 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 2014014141300 its reverse (31414104102), we get a palindrome (2045428245402).

The spelling of 2014014141300 in words is "two trillion, fourteen billion, fourteen million, one hundred forty-one thousand, three hundred".