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201401414233 is a prime number
BaseRepresentation
bin1011101110010001110…
…1011011001001011001
3201020212000021220102021
42323210131123021121
511244432230223413
6232304511134441
720356625526535
oct2734435331131
9636760256367
10201401414233
1178460936488
1233048b14421
1315cb8774576
149a68280bc5
15538b4e818d
hex2ee475b259

201401414233 has 2 divisors, whose sum is σ = 201401414234. Its totient is φ = 201401414232.

The previous prime is 201401414213. The next prime is 201401414261. The reversal of 201401414233 is 332414104102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111481196544 + 89920217689 = 333888^2 + 299867^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201401414233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201401414198 and 201401414207.

It is not a weakly prime, because it can be changed into another prime (201401414213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100700707116 + 100700707117.

It is an arithmetic number, because the mean of its divisors is an integer number (100700707117).

Almost surely, 2201401414233 is an apocalyptic number.

It is an amenable number.

201401414233 is a deficient number, since it is larger than the sum of its proper divisors (1).

201401414233 is an equidigital number, since it uses as much as digits as its factorization.

201401414233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 201401414233 its reverse (332414104102), we get a palindrome (533815518335).

The spelling of 201401414233 in words is "two hundred one billion, four hundred one million, four hundred fourteen thousand, two hundred thirty-three".