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201403101481 is a prime number
BaseRepresentation
bin1011101110010010001…
…1110111000100101001
3201020212010110121212221
42323210203313010221
511244433143221411
6232305011234041
720356646054611
oct2734443670451
9636763417787
10201403101481
11784618890aa
12330495a8921
1315cb8c1553a
149a6859da41
15538b72d071
hex2ee48f7129

201403101481 has 2 divisors, whose sum is σ = 201403101482. Its totient is φ = 201403101480.

The previous prime is 201403101469. The next prime is 201403101491. The reversal of 201403101481 is 184101304102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117022147225 + 84380954256 = 342085^2 + 290484^2 .

It is a cyclic number.

It is not a de Polignac number, because 201403101481 - 211 = 201403099433 is a prime.

It is a super-2 number, since 2×2014031014812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (201403101491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100701550740 + 100701550741.

It is an arithmetic number, because the mean of its divisors is an integer number (100701550741).

Almost surely, 2201403101481 is an apocalyptic number.

It is an amenable number.

201403101481 is a deficient number, since it is larger than the sum of its proper divisors (1).

201403101481 is an equidigital number, since it uses as much as digits as its factorization.

201403101481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 201403101481 its reverse (184101304102), we get a palindrome (385504405583).

The spelling of 201403101481 in words is "two hundred one billion, four hundred three million, one hundred one thousand, four hundred eighty-one".