Base | Representation |
---|---|
bin | 10010110000011111… |
… | …111011111110100011 |
3 | 1220222122220101212101 |
4 | 102300133323332203 |
5 | 312222101000311 |
6 | 13130324111231 |
7 | 1312053640651 |
oct | 226037737643 |
9 | 56878811771 |
10 | 20141031331 |
11 | 85a60a5a43 |
12 | 3aa1235517 |
13 | 1b8c986525 |
14 | d90d17dd1 |
15 | 7cd327ec1 |
hex | 4b07fbfa3 |
20141031331 has 2 divisors, whose sum is σ = 20141031332. Its totient is φ = 20141031330.
The previous prime is 20141031329. The next prime is 20141031341. The reversal of 20141031331 is 13313014102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20141031331 - 21 = 20141031329 is a prime.
It is a super-2 number, since 2×201410313312 (a number of 21 digits) contains 22 as substring.
Together with 20141031329, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 20141031299 and 20141031308.
It is not a weakly prime, because it can be changed into another prime (20141031341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10070515665 + 10070515666.
It is an arithmetic number, because the mean of its divisors is an integer number (10070515666).
Almost surely, 220141031331 is an apocalyptic number.
20141031331 is a deficient number, since it is larger than the sum of its proper divisors (1).
20141031331 is an equidigital number, since it uses as much as digits as its factorization.
20141031331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 20141031331 its reverse (13313014102), we get a palindrome (33454045433).
The spelling of 20141031331 in words is "twenty billion, one hundred forty-one million, thirty-one thousand, three hundred thirty-one".
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