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2014110143173 is a prime number
BaseRepresentation
bin11101010011110010010…
…100011101001011000101
321010112202210120101120101
4131103302110131023011
5230444344144040143
64141134110204101
7265341345512512
oct35236224351305
97115683511511
102014110143173
117071a7739237
122864214b3631
13117c1192880b
146d6aa838309
15375d1b1ab4d
hex1d4f251d2c5

2014110143173 has 2 divisors, whose sum is σ = 2014110143174. Its totient is φ = 2014110143172.

The previous prime is 2014110143113. The next prime is 2014110143191. The reversal of 2014110143173 is 3713410114102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1370100683169 + 644009460004 = 1170513^2 + 802502^2 .

It is a cyclic number.

It is not a de Polignac number, because 2014110143173 - 29 = 2014110142661 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2014110143113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007055071586 + 1007055071587.

It is an arithmetic number, because the mean of its divisors is an integer number (1007055071587).

Almost surely, 22014110143173 is an apocalyptic number.

It is an amenable number.

2014110143173 is a deficient number, since it is larger than the sum of its proper divisors (1).

2014110143173 is an equidigital number, since it uses as much as digits as its factorization.

2014110143173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 28.

Adding to 2014110143173 its reverse (3713410114102), we get a palindrome (5727520257275).

The spelling of 2014110143173 in words is "two trillion, fourteen billion, one hundred ten million, one hundred forty-three thousand, one hundred seventy-three".