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20141200000 = 2755431171
BaseRepresentation
bin10010110000100000…
…100101001010000000
31220222200012222020101
4102300200211022000
5312222121400000
613130331452144
71312055242465
oct226040451200
956880188211
1020141200000
1185a6200739
123aa12b7054
131b8ca1522c
14d90d5d66c
157cd35ce6a
hex4b0825280

20141200000 has 192 divisors, whose sum is σ = 51363275040. Its totient is φ = 7862400000.

The previous prime is 20141199979. The next prime is 20141200049. The reversal of 20141200000 is 214102.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is a self number, because there is not a number n which added to its sum of digits gives 20141200000.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 17199415 + ... + 17200585.

Almost surely, 220141200000 is an apocalyptic number.

20141200000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20141200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25681637520).

20141200000 is an abundant number, since it is smaller than the sum of its proper divisors (31222075040).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20141200000 is an frugal number, since it uses more digits than its factorization.

20141200000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1253 (or 1221 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 10.

Adding to 20141200000 its reverse (214102), we get a palindrome (20141414102).

The spelling of 20141200000 in words is "twenty billion, one hundred forty-one million, two hundred thousand".