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201413241433 is a prime number
BaseRepresentation
bin1011101110010100101…
…0100010101001011001
3201020212211112210021201
42323211022202221121
511244443242211213
6232310012434201
720360131206265
oct2734512425131
9636784483251
10201413241433
1178467584428
1233050a78961
1315cbb055a01
149a69a7d0a5
15538c5826dd
hex2ee52a2a59

201413241433 has 2 divisors, whose sum is σ = 201413241434. Its totient is φ = 201413241432.

The previous prime is 201413241383. The next prime is 201413241457. The reversal of 201413241433 is 334142314102.

It is a happy number.

201413241433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 188089618249 + 13323623184 = 433693^2 + 115428^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201413241433 is a prime.

It is not a weakly prime, because it can be changed into another prime (201413241473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100706620716 + 100706620717.

It is an arithmetic number, because the mean of its divisors is an integer number (100706620717).

Almost surely, 2201413241433 is an apocalyptic number.

It is an amenable number.

201413241433 is a deficient number, since it is larger than the sum of its proper divisors (1).

201413241433 is an equidigital number, since it uses as much as digits as its factorization.

201413241433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 201413241433 its reverse (334142314102), we get a palindrome (535555555535).

The spelling of 201413241433 in words is "two hundred one billion, four hundred thirteen million, two hundred forty-one thousand, four hundred thirty-three".