Base | Representation |
---|---|
bin | 11101010011110011101… |
… | …100110011000001010011 |
3 | 21010112211102010221120221 |
4 | 131103303230303001103 |
5 | 230444421111120311 |
6 | 4141140254413511 |
7 | 265342046404144 |
oct | 35236354630123 |
9 | 7115742127527 |
10 | 2014133301331 |
11 | 707209816308 |
12 | 286429201297 |
13 | 117c16676578 |
14 | 6d6ad945acb |
15 | 375d3b92671 |
hex | 1d4f3b33053 |
2014133301331 has 2 divisors, whose sum is σ = 2014133301332. Its totient is φ = 2014133301330.
The previous prime is 2014133301289. The next prime is 2014133301337. The reversal of 2014133301331 is 1331033314102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2014133301331 - 219 = 2014132777043 is a prime.
It is a super-2 number, since 2×20141333013312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2014133301296 and 2014133301305.
It is not a weakly prime, because it can be changed into another prime (2014133301337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007066650665 + 1007066650666.
It is an arithmetic number, because the mean of its divisors is an integer number (1007066650666).
Almost surely, 22014133301331 is an apocalyptic number.
2014133301331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2014133301331 is an equidigital number, since it uses as much as digits as its factorization.
2014133301331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 2014133301331 its reverse (1331033314102), we get a palindrome (3345166615433).
The spelling of 2014133301331 in words is "two trillion, fourteen billion, one hundred thirty-three million, three hundred one thousand, three hundred thirty-one".
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