Base | Representation |
---|---|
bin | 11101010011110011110… |
… | …011011000001101001111 |
3 | 21010112211112101121002111 |
4 | 131103303303120031033 |
5 | 230444422031322021 |
6 | 4141140355404451 |
7 | 265342100150626 |
oct | 35236363301517 |
9 | 7115745347074 |
10 | 2014135026511 |
11 | 70720a794483 |
12 | 2864298b3727 |
13 | 117c16b2b89a |
14 | 6d6adc746bd |
15 | 375d3dd38e1 |
hex | 1d4f3cd834f |
2014135026511 has 2 divisors, whose sum is σ = 2014135026512. Its totient is φ = 2014135026510.
The previous prime is 2014135026493. The next prime is 2014135026517. The reversal of 2014135026511 is 1156205314102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2014135026511 - 211 = 2014135024463 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2014135026517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007067513255 + 1007067513256.
It is an arithmetic number, because the mean of its divisors is an integer number (1007067513256).
Almost surely, 22014135026511 is an apocalyptic number.
2014135026511 is a deficient number, since it is larger than the sum of its proper divisors (1).
2014135026511 is an equidigital number, since it uses as much as digits as its factorization.
2014135026511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 31.
The spelling of 2014135026511 in words is "two trillion, fourteen billion, one hundred thirty-five million, twenty-six thousand, five hundred eleven".
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