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201421310324567 is a prime number
BaseRepresentation
bin101101110011000100001101…
…101001101110111101010111
3222102011200121102202111200112
4231303010031221232331113
5202400041320420341232
61552215401134233235
760266131560612644
oct5563041551567527
9872150542674615
10201421310324567
11591a73306a9923
121a71097135581b
138850c42b81b58
1437a4bb4562dcb
15184466cee94b2
hexb7310da6ef57

201421310324567 has 2 divisors, whose sum is σ = 201421310324568. Its totient is φ = 201421310324566.

The previous prime is 201421310324503. The next prime is 201421310324573. The reversal of 201421310324567 is 765423013124102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 201421310324567 - 26 = 201421310324503 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201421310320567) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100710655162283 + 100710655162284.

It is an arithmetic number, because the mean of its divisors is an integer number (100710655162284).

Almost surely, 2201421310324567 is an apocalyptic number.

201421310324567 is a deficient number, since it is larger than the sum of its proper divisors (1).

201421310324567 is an equidigital number, since it uses as much as digits as its factorization.

201421310324567 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 241920, while the sum is 41.

Adding to 201421310324567 its reverse (765423013124102), we get a palindrome (966844323448669).

The spelling of 201421310324567 in words is "two hundred one trillion, four hundred twenty-one billion, three hundred ten million, three hundred twenty-four thousand, five hundred sixty-seven".