Base | Representation |
---|---|
bin | 101101110011000110000100… |
… | …010111011111001011100011 |
3 | 222102011212202020111121222022 |
4 | 231303012010113133023203 |
5 | 202400104410304430201 |
6 | 1552220330523332055 |
7 | 60266232124050323 |
oct | 5563060427371343 |
9 | 872155666447868 |
10 | 201423302030051 |
11 | 591a81629a0712 |
12 | 1a71122838102b |
13 | 885119c6b39ca |
14 | 37a4d22c9d283 |
15 | 1844737cbe41b |
hex | b731845df2e3 |
201423302030051 has 2 divisors, whose sum is σ = 201423302030052. Its totient is φ = 201423302030050.
The previous prime is 201423302030029. The next prime is 201423302030057. The reversal of 201423302030051 is 150030203324102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201423302030051 - 238 = 201148424123107 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 201423302030051.
It is not a weakly prime, because it can be changed into another prime (201423302030057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100711651015025 + 100711651015026.
It is an arithmetic number, because the mean of its divisors is an integer number (100711651015026).
Almost surely, 2201423302030051 is an apocalyptic number.
201423302030051 is a deficient number, since it is larger than the sum of its proper divisors (1).
201423302030051 is an equidigital number, since it uses as much as digits as its factorization.
201423302030051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 26.
Adding to 201423302030051 its reverse (150030203324102), we get a palindrome (351453505354153).
The spelling of 201423302030051 in words is "two hundred one trillion, four hundred twenty-three billion, three hundred two million, thirty thousand, fifty-one".
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