Base | Representation |
---|---|
bin | 1011101110010111010… |
… | …0110110000101111011 |
3 | 201020220121102012111021 |
4 | 2323211310312011323 |
5 | 11300004112044011 |
6 | 232311050243311 |
7 | 20360324364622 |
oct | 2734564660573 |
9 | 636817365437 |
10 | 201424331131 |
11 | 78472869271 |
12 | 33054726537 |
13 | 15cc043956a |
14 | 9a6b3286b9 |
15 | 538d523471 |
hex | 2ee5d3617b |
201424331131 has 2 divisors, whose sum is σ = 201424331132. Its totient is φ = 201424331130.
The previous prime is 201424331089. The next prime is 201424331161. The reversal of 201424331131 is 131133424102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201424331131 is a prime.
It is a super-2 number, since 2×2014243311312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 201424331096 and 201424331105.
It is not a weakly prime, because it can be changed into another prime (201424331161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100712165565 + 100712165566.
It is an arithmetic number, because the mean of its divisors is an integer number (100712165566).
Almost surely, 2201424331131 is an apocalyptic number.
201424331131 is a deficient number, since it is larger than the sum of its proper divisors (1).
201424331131 is an equidigital number, since it uses as much as digits as its factorization.
201424331131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 201424331131 its reverse (131133424102), we get a palindrome (332557755233).
The spelling of 201424331131 in words is "two hundred one billion, four hundred twenty-four million, three hundred thirty-one thousand, one hundred thirty-one".
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