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20142736064251 is a prime number
BaseRepresentation
bin1001001010001110110001…
…01000001011111011111011
32122022121220220112211221221
410211013120220023323323
510120004310413024001
6110501240055212511
74146156530400613
oct445073050137373
978277826484857
1020142736064251
11646653942a7a9
122313969677137
13b315b4978758
144d8cb0dc9a43
1524de5adb31a1
hex1251d8a0befb

20142736064251 has 2 divisors, whose sum is σ = 20142736064252. Its totient is φ = 20142736064250.

The previous prime is 20142736064249. The next prime is 20142736064291. The reversal of 20142736064251 is 15246063724102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20142736064251 - 21 = 20142736064249 is a prime.

Together with 20142736064249, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 20142736064198 and 20142736064207.

It is not a weakly prime, because it can be changed into another prime (20142736064291) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10071368032125 + 10071368032126.

It is an arithmetic number, because the mean of its divisors is an integer number (10071368032126).

Almost surely, 220142736064251 is an apocalyptic number.

20142736064251 is a deficient number, since it is larger than the sum of its proper divisors (1).

20142736064251 is an equidigital number, since it uses as much as digits as its factorization.

20142736064251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 483840, while the sum is 43.

Adding to 20142736064251 its reverse (15246063724102), we get a palindrome (35388799788353).

The spelling of 20142736064251 in words is "twenty trillion, one hundred forty-two billion, seven hundred thirty-six million, sixty-four thousand, two hundred fifty-one".