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2014310013421 is a prime number
BaseRepresentation
bin11101010011111110001…
…110111001100111101101
321010120021201122212000011
4131103332032321213231
5231000301330412141
64141210010133221
7265346323416556
oct35237616714755
97116251585004
102014310013421
1170729a542762
12286478421211
13117c44168a34
146d6c91c532d
15375e444b881
hex1d4fe3b99ed

2014310013421 has 2 divisors, whose sum is σ = 2014310013422. Its totient is φ = 2014310013420.

The previous prime is 2014310013413. The next prime is 2014310013473. The reversal of 2014310013421 is 1243100134102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1413390477321 + 600919536100 = 1188861^2 + 775190^2 .

It is a cyclic number.

It is not a de Polignac number, because 2014310013421 - 23 = 2014310013413 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2014310013392 and 2014310013401.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2014310713421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007155006710 + 1007155006711.

It is an arithmetic number, because the mean of its divisors is an integer number (1007155006711).

Almost surely, 22014310013421 is an apocalyptic number.

It is an amenable number.

2014310013421 is a deficient number, since it is larger than the sum of its proper divisors (1).

2014310013421 is an equidigital number, since it uses as much as digits as its factorization.

2014310013421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 2014310013421 its reverse (1243100134102), we get a palindrome (3257410147523).

The spelling of 2014310013421 in words is "two trillion, fourteen billion, three hundred ten million, thirteen thousand, four hundred twenty-one".