Base | Representation |
---|---|
bin | 11101010011111110010… |
… | …011100000011100110011 |
3 | 21010120021210221012112220 |
4 | 131103332103200130303 |
5 | 231000302133033133 |
6 | 4141210052052123 |
7 | 265346336606412 |
oct | 35237623403463 |
9 | 7116253835486 |
10 | 2014311221043 |
11 | 7072a0197aa0 |
12 | 286478904043 |
13 | 117c4449c5c4 |
14 | 6d6c941b479 |
15 | 375e45d95b3 |
hex | 1d4fe4e0733 |
2014311221043 has 64 divisors (see below), whose sum is σ = 3132480688128. Its totient is φ = 1139070683520.
The previous prime is 2014311220939. The next prime is 2014311221063. The reversal of 2014311221043 is 3401221134102.
It is not a de Polignac number, because 2014311221043 - 29 = 2014311220531 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2014311221063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 25188480 + ... + 25268322.
It is an arithmetic number, because the mean of its divisors is an integer number (48945010752).
Almost surely, 22014311221043 is an apocalyptic number.
2014311221043 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
2014311221043 is a deficient number, since it is larger than the sum of its proper divisors (1118169467085).
2014311221043 is a wasteful number, since it uses less digits than its factorization.
2014311221043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 80696.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 2014311221043 its reverse (3401221134102), we get a palindrome (5415532355145).
The spelling of 2014311221043 in words is "two trillion, fourteen billion, three hundred eleven million, two hundred twenty-one thousand, forty-three".
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