Base | Representation |
---|---|
bin | 101101110011010000011001… |
… | …111011111001010111000111 |
3 | 222102012221101202202200112011 |
4 | 231303100121323321113013 |
5 | 202400300123214023442 |
6 | 1552225404135435051 |
7 | 60300104150314423 |
oct | 5563203173712707 |
9 | 872187352680464 |
10 | 201434401314247 |
11 | 59201939181162 |
12 | 1a713405525a87 |
13 | 885224b0610aa |
14 | 37a5697015b83 |
15 | 1844b87421117 |
hex | b73419ef95c7 |
201434401314247 has 2 divisors, whose sum is σ = 201434401314248. Its totient is φ = 201434401314246.
The previous prime is 201434401314197. The next prime is 201434401314259. The reversal of 201434401314247 is 742413104434102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201434401314247 - 215 = 201434401281479 is a prime.
It is a super-2 number, since 2×2014344013142472 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201434408314247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100717200657123 + 100717200657124.
It is an arithmetic number, because the mean of its divisors is an integer number (100717200657124).
Almost surely, 2201434401314247 is an apocalyptic number.
201434401314247 is a deficient number, since it is larger than the sum of its proper divisors (1).
201434401314247 is an equidigital number, since it uses as much as digits as its factorization.
201434401314247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 258048, while the sum is 40.
Adding to 201434401314247 its reverse (742413104434102), we get a palindrome (943847505748349).
The spelling of 201434401314247 in words is "two hundred one trillion, four hundred thirty-four billion, four hundred one million, three hundred fourteen thousand, two hundred forty-seven".
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