Base | Representation |
---|---|
bin | 11101010100000100010… |
… | …001011100010100100001 |
3 | 21010120112210022221020121 |
4 | 131110010101130110201 |
5 | 231001003300440022 |
6 | 4141224030040241 |
7 | 265351663620514 |
oct | 35240421342441 |
9 | 7116483287217 |
10 | 2014411343137 |
11 | 707341762226 |
12 | 2864a6349081 |
13 | 117c5c15684b |
14 | 6d6d8840d7b |
15 | 375ed2b52c7 |
hex | 1d50445c521 |
2014411343137 has 2 divisors, whose sum is σ = 2014411343138. Its totient is φ = 2014411343136.
The previous prime is 2014411343129. The next prime is 2014411343167. The reversal of 2014411343137 is 7313431144102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1989366381601 + 25044961536 = 1410449^2 + 158256^2 .
It is a cyclic number.
It is not a de Polignac number, because 2014411343137 - 23 = 2014411343129 is a prime.
It is not a weakly prime, because it can be changed into another prime (2014411343167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007205671568 + 1007205671569.
It is an arithmetic number, because the mean of its divisors is an integer number (1007205671569).
Almost surely, 22014411343137 is an apocalyptic number.
It is an amenable number.
2014411343137 is a deficient number, since it is larger than the sum of its proper divisors (1).
2014411343137 is an equidigital number, since it uses as much as digits as its factorization.
2014411343137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 34.
Adding to 2014411343137 its reverse (7313431144102), we get a palindrome (9327842487239).
The spelling of 2014411343137 in words is "two trillion, fourteen billion, four hundred eleven million, three hundred forty-three thousand, one hundred thirty-seven".
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