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20144133313 is a prime number
BaseRepresentation
bin10010110000101011…
…110001010011000001
31220222212201222222121
4102300223301103001
5312223344231223
613130514404241
71312122210433
oct226053612301
956885658877
1020144133313
1185a7924567
123aa2290681
131b90501415
14d914c4653
157cd73c15d
hex4b0af14c1

20144133313 has 2 divisors, whose sum is σ = 20144133314. Its totient is φ = 20144133312.

The previous prime is 20144133301. The next prime is 20144133329. The reversal of 20144133313 is 31333144102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19718618929 + 425514384 = 140423^2 + 20628^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20144133313 is a prime.

It is a super-2 number, since 2×201441333132 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20144130313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10072066656 + 10072066657.

It is an arithmetic number, because the mean of its divisors is an integer number (10072066657).

Almost surely, 220144133313 is an apocalyptic number.

It is an amenable number.

20144133313 is a deficient number, since it is larger than the sum of its proper divisors (1).

20144133313 is an equidigital number, since it uses as much as digits as its factorization.

20144133313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 20144133313 its reverse (31333144102), we get a palindrome (51477277415).

The spelling of 20144133313 in words is "twenty billion, one hundred forty-four million, one hundred thirty-three thousand, three hundred thirteen".