Base | Representation |
---|---|
bin | 1011101110011011100… |
… | …0110010011101100011 |
3 | 201020221211221002110222 |
4 | 2323212320302131203 |
5 | 11300023142021201 |
6 | 232312524113255 |
7 | 20360631645533 |
oct | 2734670623543 |
9 | 636854832428 |
10 | 201442142051 |
11 | 78481923937 |
12 | 3305a69582b |
13 | 15cc4034477 |
14 | 9a6d8434c3 |
15 | 538ed9091b |
hex | 2ee6e32763 |
201442142051 has 2 divisors, whose sum is σ = 201442142052. Its totient is φ = 201442142050.
The previous prime is 201442142047. The next prime is 201442142053. The reversal of 201442142051 is 150241244102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201442142051 - 22 = 201442142047 is a prime.
Together with 201442142053, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 201442142051.
It is not a weakly prime, because it can be changed into another prime (201442142053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100721071025 + 100721071026.
It is an arithmetic number, because the mean of its divisors is an integer number (100721071026).
Almost surely, 2201442142051 is an apocalyptic number.
201442142051 is a deficient number, since it is larger than the sum of its proper divisors (1).
201442142051 is an equidigital number, since it uses as much as digits as its factorization.
201442142051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2560, while the sum is 26.
Adding to 201442142051 its reverse (150241244102), we get a palindrome (351683386153).
The spelling of 201442142051 in words is "two hundred one billion, four hundred forty-two million, one hundred forty-two thousand, fifty-one".
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