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201442142051 is a prime number
BaseRepresentation
bin1011101110011011100…
…0110010011101100011
3201020221211221002110222
42323212320302131203
511300023142021201
6232312524113255
720360631645533
oct2734670623543
9636854832428
10201442142051
1178481923937
123305a69582b
1315cc4034477
149a6d8434c3
15538ed9091b
hex2ee6e32763

201442142051 has 2 divisors, whose sum is σ = 201442142052. Its totient is φ = 201442142050.

The previous prime is 201442142047. The next prime is 201442142053. The reversal of 201442142051 is 150241244102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 201442142051 - 22 = 201442142047 is a prime.

Together with 201442142053, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 201442142051.

It is not a weakly prime, because it can be changed into another prime (201442142053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100721071025 + 100721071026.

It is an arithmetic number, because the mean of its divisors is an integer number (100721071026).

Almost surely, 2201442142051 is an apocalyptic number.

201442142051 is a deficient number, since it is larger than the sum of its proper divisors (1).

201442142051 is an equidigital number, since it uses as much as digits as its factorization.

201442142051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2560, while the sum is 26.

Adding to 201442142051 its reverse (150241244102), we get a palindrome (351683386153).

The spelling of 201442142051 in words is "two hundred one billion, four hundred forty-two million, one hundred forty-two thousand, fifty-one".