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2014433117 is a prime number
BaseRepresentation
bin111100000010001…
…1100111101011101
312012101111210201222
41320010130331131
513111143324432
6531520143125
7100630253564
oct17004347535
95171453658
102014433117
11944105464
12482767aa5
1326145b978
14151774bdb
15bbcb4112
hex7811cf5d

2014433117 has 2 divisors, whose sum is σ = 2014433118. Its totient is φ = 2014433116.

The previous prime is 2014433107. The next prime is 2014433123. The reversal of 2014433117 is 7113344102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1201384921 + 813048196 = 34661^2 + 28514^2 .

It is a cyclic number.

It is not a de Polignac number, because 2014433117 - 24 = 2014433101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2014433107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007216558 + 1007216559.

It is an arithmetic number, because the mean of its divisors is an integer number (1007216559).

Almost surely, 22014433117 is an apocalyptic number.

It is an amenable number.

2014433117 is a deficient number, since it is larger than the sum of its proper divisors (1).

2014433117 is an equidigital number, since it uses as much as digits as its factorization.

2014433117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 26.

The square root of 2014433117 is about 44882.4366205758. The cubic root of 2014433117 is about 1262.9445530748.

Adding to 2014433117 its reverse (7113344102), we get a palindrome (9127777219).

The spelling of 2014433117 in words is "two billion, fourteen million, four hundred thirty-three thousand, one hundred seventeen".