Search a number
-
+
20144503425751 is a prime number
BaseRepresentation
bin1001001010010010000011…
…11110001000101011010111
32122022210111002011010011021
410211021001332020223113
510120021420334111001
6110502131312022011
74146251400620215
oct445110176105327
978283432133137
1020144503425751
116467266021641
122314181531907
13b31806b7b8a3
144d8ddba07cb5
1524e011120ba1
hex125241f88ad7

20144503425751 has 2 divisors, whose sum is σ = 20144503425752. Its totient is φ = 20144503425750.

The previous prime is 20144503425731. The next prime is 20144503425757. The reversal of 20144503425751 is 15752430544102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20144503425751 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20144503425698 and 20144503425707.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20144503425757) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10072251712875 + 10072251712876.

It is an arithmetic number, because the mean of its divisors is an integer number (10072251712876).

Almost surely, 220144503425751 is an apocalyptic number.

20144503425751 is a deficient number, since it is larger than the sum of its proper divisors (1).

20144503425751 is an equidigital number, since it uses as much as digits as its factorization.

20144503425751 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 672000, while the sum is 43.

Adding to 20144503425751 its reverse (15752430544102), we get a palindrome (35896933969853).

The spelling of 20144503425751 in words is "twenty trillion, one hundred forty-four billion, five hundred three million, four hundred twenty-five thousand, seven hundred fifty-one".