Base | Representation |
---|---|
bin | 11101010100001100001… |
… | …011110111111111100111 |
3 | 21010120220001010202021111 |
4 | 131110030023313333213 |
5 | 231001241242220401 |
6 | 4141245131325451 |
7 | 265355165216635 |
oct | 35241413677747 |
9 | 7116801122244 |
10 | 2014544101351 |
11 | 7073aa698461 |
12 | 2865228b0887 |
13 | 117c807c98c2 |
14 | 6d70c31c355 |
15 | 37609c8ae51 |
hex | 1d50c2f7fe7 |
2014544101351 has 2 divisors, whose sum is σ = 2014544101352. Its totient is φ = 2014544101350.
The previous prime is 2014544101319. The next prime is 2014544101397. The reversal of 2014544101351 is 1531014454102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2014544101351 - 25 = 2014544101319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2014544101051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007272050675 + 1007272050676.
It is an arithmetic number, because the mean of its divisors is an integer number (1007272050676).
Almost surely, 22014544101351 is an apocalyptic number.
2014544101351 is a deficient number, since it is larger than the sum of its proper divisors (1).
2014544101351 is an equidigital number, since it uses as much as digits as its factorization.
2014544101351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 2014544101351 its reverse (1531014454102), we get a palindrome (3545558555453).
The spelling of 2014544101351 in words is "two trillion, fourteen billion, five hundred forty-four million, one hundred one thousand, three hundred fifty-one".
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