20150144351 has 2 divisors, whose sum is σ = 20150144352. Its totient is φ = 20150144350.

The previous prime is 20150144321. The next prime is 20150144383. The reversal of 20150144351 is 15344105102.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-20150144351 is a prime.

It is a super-2 number, since 2×20150144351² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 20150144351.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20150144321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10075072175 + 10075072176.

It is an arithmetic number, because the mean of its divisors is an integer number (10075072176).

Almost surely, 2^20150144351 is an apocalyptic number.

20150144351 is a deficient number, since it is larger than the sum of its proper divisors (1).

20150144351 is an equidigital number, since it uses as much as digits as its factorization.

20150144351 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 20150144351 its reverse (15344105102), we get a palindrome (35494249453).

The spelling of 20150144351 in words is "twenty billion, one hundred fifty million, one hundred forty-four thousand, three hundred fifty-one".