| Base | Representation |
|---|---|
| bin | 11101010100101001001… |
| … | …110100101001101100000 |
| 3 | 21010122010222222112220220 |
| 4 | 131110221032211031200 |
| 5 | 231003241011200422 |
| 6 | 4141405335003040 |
| 7 | 265403232605154 |
| oct | 35245116451540 |
| 9 | 7118128875826 |
| 10 | 2015031350112 |
| 11 | 70762a735690 |
| 12 | 286639b09480 |
| 13 | 11802a738a91 |
| 14 | 6d756d15064 |
| 15 | 37637935e5c |
| hex | 1d5293a5360 |
2015031350112 has 192 divisors, whose sum is σ = 5796218953728. Its totient is φ = 607881024000.
The previous prime is 2015031350107. The next prime is 2015031350117. The reversal of 2015031350112 is 2110531305102.
It is an interprime number because it is at equal distance from previous prime (2015031350107) and next prime (2015031350117).
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2015031350117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 221646687 + ... + 221655777.
It is an arithmetic number, because the mean of its divisors is an integer number (30188640384).
Almost surely, 22015031350112 is an apocalyptic number.
2015031350112 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 2015031350112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2898109476864).
2015031350112 is an abundant number, since it is smaller than the sum of its proper divisors (3781187603616).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2015031350112 is a wasteful number, since it uses less digits than its factorization.
2015031350112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10033 (or 10025 counting only the distinct ones).
The product of its (nonzero) digits is 900, while the sum is 24.
Adding to 2015031350112 its reverse (2110531305102), we get a palindrome (4125562655214).
The spelling of 2015031350112 in words is "two trillion, fifteen billion, thirty-one million, three hundred fifty thousand, one hundred twelve".
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