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20150346761 is a prime number
BaseRepresentation
bin10010110001000011…
…011110010000001001
31221000022102200020022
4102301003132100021
5312231442044021
613131255510225
71312226056436
oct226103362011
957008380208
1020150346761
118600388846
123aa4388375
131b9189860c
14d92260b8d
157ce0681ab
hex4b10de409

20150346761 has 2 divisors, whose sum is σ = 20150346762. Its totient is φ = 20150346760.

The previous prime is 20150346743. The next prime is 20150346763. The reversal of 20150346761 is 16764305102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12261354361 + 7888992400 = 110731^2 + 88820^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20150346761 is a prime.

It is a super-2 number, since 2×201503467612 (a number of 21 digits) contains 22 as substring.

Together with 20150346763, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (20150346763) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10075173380 + 10075173381.

It is an arithmetic number, because the mean of its divisors is an integer number (10075173381).

Almost surely, 220150346761 is an apocalyptic number.

It is an amenable number.

20150346761 is a deficient number, since it is larger than the sum of its proper divisors (1).

20150346761 is an equidigital number, since it uses as much as digits as its factorization.

20150346761 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30240, while the sum is 35.

The spelling of 20150346761 in words is "twenty billion, one hundred fifty million, three hundred forty-six thousand, seven hundred sixty-one".