Base | Representation |
---|---|
bin | 11101010100101111110… |
… | …100110110000101111001 |
3 | 21010122102201021101102110 |
4 | 131110233310312011321 |
5 | 231004002330402100 |
6 | 4141424331322533 |
7 | 265406045520015 |
oct | 35245764660571 |
9 | 7118381241373 |
10 | 2015142044025 |
11 | 707687170660 |
12 | 28666abb0449 |
13 | 118047654c36 |
14 | 6d7678cb545 |
15 | 376424ee250 |
hex | 1d52fd36179 |
2015142044025 has 24 divisors (see below), whose sum is σ = 3634583469984. Its totient is φ = 977038566400.
The previous prime is 2015142044011. The next prime is 2015142044051. The reversal of 2015142044025 is 5204402415102.
It is not a de Polignac number, because 2015142044025 - 24 = 2015142044009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2015142043983 and 2015142044001.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1221297384 + ... + 1221299033.
It is an arithmetic number, because the mean of its divisors is an integer number (151440977916).
Almost surely, 22015142044025 is an apocalyptic number.
2015142044025 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
2015142044025 is a deficient number, since it is larger than the sum of its proper divisors (1619441425959).
2015142044025 is a wasteful number, since it uses less digits than its factorization.
2015142044025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2442596441 (or 2442596436 counting only the distinct ones).
The product of its (nonzero) digits is 12800, while the sum is 30.
Adding to 2015142044025 its reverse (5204402415102), we get a palindrome (7219544459127).
The spelling of 2015142044025 in words is "two trillion, fifteen billion, one hundred forty-two million, forty-four thousand, twenty-five".
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