Search a number
-
+
20151453103 = 130115489203
BaseRepresentation
bin10010110001000111…
…101100010110101111
31221000101111212211221
4102301013230112233
5312232232444403
613131335324211
71312241345065
oct226107542657
957011455757
1020151453103
118600a73a81
123aa4820667
131b91b95062
14d9246c035
157ce1d5dbd
hex4b11ec5af

20151453103 has 4 divisors (see below), whose sum is σ = 20166943608. Its totient is φ = 20135962600.

The previous prime is 20151453061. The next prime is 20151453109. The reversal of 20151453103 is 30135415102.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20151453103 - 217 = 20151322031 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20151453109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7743301 + ... + 7745902.

It is an arithmetic number, because the mean of its divisors is an integer number (5041735902).

Almost surely, 220151453103 is an apocalyptic number.

20151453103 is a deficient number, since it is larger than the sum of its proper divisors (15490505).

20151453103 is a wasteful number, since it uses less digits than its factorization.

20151453103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15490504.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 20151453103 its reverse (30135415102), we get a palindrome (50286868205).

The spelling of 20151453103 in words is "twenty billion, one hundred fifty-one million, four hundred fifty-three thousand, one hundred three".

Divisors: 1 1301 15489203 20151453103