Base | Representation |
---|---|
bin | 11101010100110000000… |
… | …010000101000000011011 |
3 | 21010122102221210121221112 |
4 | 131110300002011000123 |
5 | 231004004222403422 |
6 | 4141424533530535 |
7 | 265406120145425 |
oct | 35246002050033 |
9 | 7118387717845 |
10 | 2015145512987 |
11 | 70768911a972 |
12 | 2866701a3a4b |
13 | 11804829ab89 |
14 | 6d768151815 |
15 | 37642986ee2 |
hex | 1d53008501b |
2015145512987 has 2 divisors, whose sum is σ = 2015145512988. Its totient is φ = 2015145512986.
The previous prime is 2015145512981. The next prime is 2015145513041. The reversal of 2015145512987 is 7892155415102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2015145512987 - 24 = 2015145512971 is a prime.
It is a super-2 number, since 2×20151455129872 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2015145512981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007572756493 + 1007572756494.
It is an arithmetic number, because the mean of its divisors is an integer number (1007572756494).
Almost surely, 22015145512987 is an apocalyptic number.
2015145512987 is a deficient number, since it is larger than the sum of its proper divisors (1).
2015145512987 is an equidigital number, since it uses as much as digits as its factorization.
2015145512987 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008000, while the sum is 50.
The spelling of 2015145512987 in words is "two trillion, fifteen billion, one hundred forty-five million, five hundred twelve thousand, nine hundred eighty-seven".
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