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2015145513041 is a prime number
BaseRepresentation
bin11101010100110000000…
…010000101000001010001
321010122102221210122000112
4131110300002011001101
5231004004222404131
64141424533531105
7265406120145533
oct35246002050121
97118387718015
102015145513041
1170768911aa11
122866701a3a95
1311804829abcb
146d768151853
153764298702b
hex1d530085051

2015145513041 has 2 divisors, whose sum is σ = 2015145513042. Its totient is φ = 2015145513040.

The previous prime is 2015145512987. The next prime is 2015145513053. The reversal of 2015145513041 is 1403155415102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1774330561600 + 240814951441 = 1332040^2 + 490729^2 .

It is a cyclic number.

It is not a de Polignac number, because 2015145513041 - 214 = 2015145496657 is a prime.

It is a super-2 number, since 2×20151455130412 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2015145512989 and 2015145513007.

It is not a weakly prime, because it can be changed into another prime (2015145513071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007572756520 + 1007572756521.

It is an arithmetic number, because the mean of its divisors is an integer number (1007572756521).

Almost surely, 22015145513041 is an apocalyptic number.

It is an amenable number.

2015145513041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2015145513041 is an equidigital number, since it uses as much as digits as its factorization.

2015145513041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12000, while the sum is 32.

The spelling of 2015145513041 in words is "two trillion, fifteen billion, one hundred forty-five million, five hundred thirteen thousand, forty-one".