201520130443 has 2 divisors, whose sum is σ = 201520130444. Its totient is φ = 201520130442.

The previous prime is 201520130431. The next prime is 201520130477. The reversal of 201520130443 is 344031025102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 201520130443 - 2⁵ = 201520130411 is a prime.

It is a super-2 number, since 2×201520130443² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (201520130743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100760065221 + 100760065222.

It is an arithmetic number, because the mean of its divisors is an integer number (100760065222).

Almost surely, 2^201520130443 is an apocalyptic number.

201520130443 is a deficient number, since it is larger than the sum of its proper divisors (1).

201520130443 is an equidigital number, since it uses as much as digits as its factorization.

201520130443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 201520130443 its reverse (344031025102), we get a palindrome (545551155545).

The spelling of 201520130443 in words is "two hundred one billion, five hundred twenty million, one hundred thirty thousand, four hundred forty-three".