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201520141 is a prime number
BaseRepresentation
bin11000000001011…
…11010000001101
3112001012021122221
430000233100031
5403042121031
631555135341
74664615164
oct1400572015
9461167587
10201520141
11a3831079
12575a4551
133299a1b4
141ca9a3db
1512a59a11
hexc02f40d

201520141 has 2 divisors, whose sum is σ = 201520142. Its totient is φ = 201520140.

The previous prime is 201520133. The next prime is 201520177. The reversal of 201520141 is 141025102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 201044041 + 476100 = 14179^2 + 690^2 .

It is a cyclic number.

It is not a de Polignac number, because 201520141 - 23 = 201520133 is a prime.

It is a super-2 number, since 2×2015201412 = 81220734457319762, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201521141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100760070 + 100760071.

It is an arithmetic number, because the mean of its divisors is an integer number (100760071).

Almost surely, 2201520141 is an apocalyptic number.

It is an amenable number.

201520141 is a deficient number, since it is larger than the sum of its proper divisors (1).

201520141 is an equidigital number, since it uses as much as digits as its factorization.

201520141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 80, while the sum is 16.

The square root of 201520141 is about 14195.7789853181. The cubic root of 201520141 is about 586.2814493277.

Adding to 201520141 its reverse (141025102), we get a palindrome (342545243).

The spelling of 201520141 in words is "two hundred one million, five hundred twenty thousand, one hundred forty-one".