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20152110423241 is a prime number
BaseRepresentation
bin1001001010100000001110…
…11000100001110011001001
32122100112010020001121222001
410211100013120201303021
510120133010232020431
6110505430212231001
74146641040211366
oct445200730416311
978315106047861
1020152110423241
11646a509a73425
12231574500b461
13b32449b60434
144d952000d46d
1524e308d8ae61
hex125407621cc9

20152110423241 has 2 divisors, whose sum is σ = 20152110423242. Its totient is φ = 20152110423240.

The previous prime is 20152110423217. The next prime is 20152110423253. The reversal of 20152110423241 is 14232401125102.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18422809152400 + 1729301270841 = 4292180^2 + 1315029^2 .

It is a cyclic number.

It is not a de Polignac number, because 20152110423241 - 213 = 20152110415049 is a prime.

It is a super-2 number, since 2×201521104232412 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20152110423941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10076055211620 + 10076055211621.

It is an arithmetic number, because the mean of its divisors is an integer number (10076055211621).

Almost surely, 220152110423241 is an apocalyptic number.

It is an amenable number.

20152110423241 is a deficient number, since it is larger than the sum of its proper divisors (1).

20152110423241 is an equidigital number, since it uses as much as digits as its factorization.

20152110423241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 20152110423241 its reverse (14232401125102), we get a palindrome (34384511548343).

The spelling of 20152110423241 in words is "twenty trillion, one hundred fifty-two billion, one hundred ten million, four hundred twenty-three thousand, two hundred forty-one".