Base | Representation |
---|---|
bin | 10010110001001011… |
… | …011011001000010101 |
3 | 1221000110100120102222 |
4 | 102301023123020111 |
5 | 312233010244000 |
6 | 13131412312125 |
7 | 1312252560341 |
oct | 226113331025 |
9 | 57013316388 |
10 | 20152431125 |
11 | 8601581862 |
12 | 3aa5012645 |
13 | 1b92148278 |
14 | d92644621 |
15 | 7ce32aa85 |
hex | 4b12db215 |
20152431125 has 32 divisors (see below), whose sum is σ = 26950734720. Its totient is φ = 14990649600.
The previous prime is 20152431107. The next prime is 20152431181. The reversal of 20152431125 is 52113425102.
It is not a de Polignac number, because 20152431125 - 220 = 20151382549 is a prime.
It is a super-2 number, since 2×201524311252 (a number of 21 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 20152431094 and 20152431103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 119246 + ... + 233504.
It is an arithmetic number, because the mean of its divisors is an integer number (842210460).
Almost surely, 220152431125 is an apocalyptic number.
20152431125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
20152431125 is a deficient number, since it is larger than the sum of its proper divisors (6798303595).
20152431125 is a wasteful number, since it uses less digits than its factorization.
20152431125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 114374 (or 114364 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 26.
Adding to 20152431125 its reverse (52113425102), we get a palindrome (72265856227).
The spelling of 20152431125 in words is "twenty billion, one hundred fifty-two million, four hundred thirty-one thousand, one hundred twenty-five".
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