Base | Representation |
---|---|
bin | 10010110001001011… |
… | …100000100000011011 |
3 | 1221000110101200122121 |
4 | 102301023200200123 |
5 | 312233012000042 |
6 | 13131413002111 |
7 | 1312253011501 |
oct | 226113404033 |
9 | 57013350577 |
10 | 20152453147 |
11 | 8601597362 |
12 | 3aa5023337 |
13 | 1b921552b8 |
14 | d9264c671 |
15 | 7ce332367 |
hex | 4b12e081b |
20152453147 has 2 divisors, whose sum is σ = 20152453148. Its totient is φ = 20152453146.
The previous prime is 20152453121. The next prime is 20152453163. The reversal of 20152453147 is 74135425102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20152453147 is a prime.
It is a super-2 number, since 2×201524531472 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20152453187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10076226573 + 10076226574.
It is an arithmetic number, because the mean of its divisors is an integer number (10076226574).
Almost surely, 220152453147 is an apocalyptic number.
20152453147 is a deficient number, since it is larger than the sum of its proper divisors (1).
20152453147 is an equidigital number, since it uses as much as digits as its factorization.
20152453147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 33600, while the sum is 34.
Adding to 20152453147 its reverse (74135425102), we get a palindrome (94287878249).
The spelling of 20152453147 in words is "twenty billion, one hundred fifty-two million, four hundred fifty-three thousand, one hundred forty-seven".
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