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20154050051 = 83692408179
BaseRepresentation
bin10010110001010001…
…100110011000000011
31221000120101211012012
4102301101212120003
5312233414100201
613131511123135
71312302412262
oct226121463003
957016354165
1020154050051
118602488113
123aa56734ab
131b92594105
14d929465d9
157ce54a5bb
hex4b1466603

20154050051 has 4 divisors (see below), whose sum is σ = 20156466600. Its totient is φ = 20151633504.

The previous prime is 20154050017. The next prime is 20154050087. The reversal of 20154050051 is 15005045102.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15005045102 = 27502522551.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20154050051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20154049999 and 20154050026.

It is not an unprimeable number, because it can be changed into a prime (20154050551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1195721 + ... + 1212458.

It is an arithmetic number, because the mean of its divisors is an integer number (5039116650).

Almost surely, 220154050051 is an apocalyptic number.

20154050051 is a deficient number, since it is larger than the sum of its proper divisors (2416549).

20154050051 is an equidigital number, since it uses as much as digits as its factorization.

20154050051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2416548.

The product of its (nonzero) digits is 1000, while the sum is 23.

Adding to 20154050051 its reverse (15005045102), we get a palindrome (35159095153).

The spelling of 20154050051 in words is "twenty billion, one hundred fifty-four million, fifty thousand, fifty-one".

Divisors: 1 8369 2408179 20154050051