Base | Representation |
---|---|
bin | 10010110001010001… |
… | …100110011111110111 |
3 | 1221000120101211212201 |
4 | 102301101212133313 |
5 | 312233414104201 |
6 | 13131511125331 |
7 | 1312302413605 |
oct | 226121463767 |
9 | 57016354781 |
10 | 20154050551 |
11 | 8602488528 |
12 | 3aa5673847 |
13 | 1b925943cb |
14 | d92946875 |
15 | 7ce54a801 |
hex | 4b14667f7 |
20154050551 has 2 divisors, whose sum is σ = 20154050552. Its totient is φ = 20154050550.
The previous prime is 20154050533. The next prime is 20154050563. The reversal of 20154050551 is 15505045102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20154050551 - 217 = 20153919479 is a prime.
It is a super-2 number, since 2×201540505512 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20154056551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10077025275 + 10077025276.
It is an arithmetic number, because the mean of its divisors is an integer number (10077025276).
Almost surely, 220154050551 is an apocalyptic number.
20154050551 is a deficient number, since it is larger than the sum of its proper divisors (1).
20154050551 is an equidigital number, since it uses as much as digits as its factorization.
20154050551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5000, while the sum is 28.
Adding to 20154050551 its reverse (15505045102), we get a palindrome (35659095653).
The spelling of 20154050551 in words is "twenty billion, one hundred fifty-four million, fifty thousand, five hundred fifty-one".
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