Base | Representation |
---|---|
bin | 10010110001010010… |
… | …011000001111010101 |
3 | 1221000120210012100201 |
4 | 102301102120033111 |
5 | 312233442114133 |
6 | 13131515340501 |
7 | 1312304222605 |
oct | 226122301725 |
9 | 57016705321 |
10 | 20154254293 |
11 | 8602607608 |
12 | 3aa5751731 |
13 | 1b92636074 |
14 | d9299ac05 |
15 | 7ce58ad7d |
hex | 4b14983d5 |
20154254293 has 2 divisors, whose sum is σ = 20154254294. Its totient is φ = 20154254292.
The previous prime is 20154254231. The next prime is 20154254299. The reversal of 20154254293 is 39245245102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20057074129 + 97180164 = 141623^2 + 9858^2 .
It is a cyclic number.
It is not a de Polignac number, because 20154254293 - 225 = 20120699861 is a prime.
It is a super-2 number, since 2×201542542932 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20154254299) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10077127146 + 10077127147.
It is an arithmetic number, because the mean of its divisors is an integer number (10077127147).
Almost surely, 220154254293 is an apocalyptic number.
It is an amenable number.
20154254293 is a deficient number, since it is larger than the sum of its proper divisors (1).
20154254293 is an equidigital number, since it uses as much as digits as its factorization.
20154254293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 37.
Adding to 20154254293 its reverse (39245245102), we get a palindrome (59399499395).
The spelling of 20154254293 in words is "twenty billion, one hundred fifty-four million, two hundred fifty-four thousand, two hundred ninety-three".
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