Base | Representation |
---|---|
bin | 10010110001010010… |
… | …100110010101100011 |
3 | 1221000120220010120022 |
4 | 102301102212111203 |
5 | 312234000441120 |
6 | 13131520504055 |
7 | 1312304553134 |
oct | 226122462543 |
9 | 57016803508 |
10 | 20154312035 |
11 | 8602646a30 |
12 | 3aa577b02b |
13 | 1b92656430 |
14 | d929b3c8b |
15 | 7ce59d025 |
hex | 4b14a6563 |
20154312035 has 64 divisors (see below), whose sum is σ = 29968081920. Its totient is φ = 12792660480.
The previous prime is 20154312019. The next prime is 20154312041. The reversal of 20154312035 is 53021345102.
It is a happy number.
It is not a de Polignac number, because 20154312035 - 24 = 20154312019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20154311995 and 20154312013.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8788349 + ... + 8790641.
It is an arithmetic number, because the mean of its divisors is an integer number (468251280).
Almost surely, 220154312035 is an apocalyptic number.
20154312035 is a deficient number, since it is larger than the sum of its proper divisors (9813769885).
20154312035 is a wasteful number, since it uses less digits than its factorization.
20154312035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2988.
The product of its (nonzero) digits is 3600, while the sum is 26.
Adding to 20154312035 its reverse (53021345102), we get a palindrome (73175657137).
The spelling of 20154312035 in words is "twenty billion, one hundred fifty-four million, three hundred twelve thousand, thirty-five".
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