2015436236551 has 2 divisors, whose sum is σ = 2015436236552. Its totient is φ = 2015436236550.

The previous prime is 2015436236531. The next prime is 2015436236659. The reversal of 2015436236551 is 1556326345102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2015436236551 - 2¹⁷ = 2015436105479 is a prime.

It is a super-3 number, since 3×2015436236551³ (a number of 38 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2015436236498 and 2015436236507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2015436236501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007718118275 + 1007718118276.

It is an arithmetic number, because the mean of its divisors is an integer number (1007718118276).

Almost surely, 2^{2015436236551} is an apocalyptic number.

2015436236551 is a deficient number, since it is larger than the sum of its proper divisors (1).

2015436236551 is an equidigital number, since it uses as much as digits as its factorization.

2015436236551 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648000, while the sum is 43.

The spelling of 2015436236551 in words is "two trillion, fifteen billion, four hundred thirty-six million, two hundred thirty-six thousand, five hundred fifty-one".